Ratios, rates, proportions and units
Unit conversion is the dominant error source here. Dimensional analysis makes it mechanical.
~30 min · prequestion, worked examples, retrieval practice
A rate is a fraction that remembers what its numbers were measuring, and almost every point lost in this domain is lost the moment the fraction forgets. The arithmetic here is the simplest on the Math section — multiply, divide, cross-multiply — which is precisely why the exam does not test the arithmetic. It tests whether milligrams stayed milligrams, whether an area conversion got squared, and whether the number you finally wrote answers the quantity the last line asked for. Problem-Solving and Data Analysis is about 15% of the Math section under College Board's published domain weights, roughly five to seven questions, and this skill is the floor the rest of that domain stands on.
Before you read on
Two or three questions on exactly what this lesson teaches. Being wrong here is fine — it's the fastest way to find out what to pay attention to next.
Before any teaching. A pipeline carries 3,600 gallons per hour, and you want that figure in gallons per minute. You are going to multiply by a fraction built from "1 hour = 60 minutes." Which fraction, and why?
A rectangular plot has an area of 2 square meters. Given that 1 meter = 100 centimeters, what is its area in square centimeters?
A taxi charges a $4 flat fee plus $2 for each mile driven, so a 5-mile ride costs $14. What does a 10-mile ride cost?
What the question is actually testing
Four ideas the exam treats as one skill: a ratio (a comparison of two quantities by division), a rate (a ratio of quantities measured in different units), a proportion (two ratios set equal to each other), and unit conversion (rewriting a quantity in different units without changing what it is). Items arrive as a short paragraph of context, sometimes attached to a table or a graph, and roughly a quarter of Math questions are — so on a share of these there are no choices to check yourself against.
The arithmetic is deliberately easy. No item in this skill will ask you to do anything harder than multiply and divide, and the calculator is available on every question. The difficulty is manufactured almost entirely by units: a rate stated per 100 kilometers instead of per kilometer, a mass in grams and a price in kilograms, an area in square centimeters and a coverage figure in square meters. Take the units out of these questions and most of them become one line of arithmetic. That is the design, and it tells you where to spend your attention.
What is supplied and what is not. The on-screen carries geometry formulas only — no conversion table of any kind. In released material an unusual conversion is stated inside the question (1 furlong = 220 yards), while everyday ones are assumed (60 seconds in a minute, 100 centimeters in a meter, 1,000 grams in a kilogram, 1,000 milliliters in a liter). That pattern is an observation about released items and the prep industry's reading of it, not a printed College Board guarantee — so treat the everyday metric and time conversions as things you already know cold, and do not count on a factor being handed to you.
Foundations — ratios, rates and proportions from zero (skip this block if "3 quarts every 2 minutes, in quarts per hour" is instant)
If you can already turn any "per" statement into a fraction and set up a proportion without thinking about it, skip to the next block; nothing here will be new. If any of the four words in the title is vague, this is the highest-value block on the page, because these four ideas also carry the percentages, probability and data-analysis questions that come later.
A ratio compares two quantities by dividing them. "5 to 3", "5:3" and "5/3" all say the same thing: for every 5 units of the first quantity there are 3 of the second. Notice what a ratio does not tell you — the actual amounts. The ratio 5:3 fits 5 and 3, and 50 and 30, and 12.5 and 7.5 equally well.
The most useful move with any ratio is to count parts. A ratio of 5:3 describes 5 + 3 = 8 parts in total. If the total is 72 kilograms, one part is 72 ÷ 8 = 9 kilograms, so the two quantities are 45 and 27. Once you have the value of one part, every question about that mixture is a multiplication. And note the distinction the exam leans on hardest: 5/8 and 3/8 are the shares of the whole, while 5/3 is the comparison of the two parts. They are different numbers answering different questions.
A rate is a ratio whose two quantities are measured in different units — miles and hours, dollars and pounds, milligrams and square centimeters. The word "per" is a fraction bar and nothing else: "miles per hour" means miles divided by hours. A unit rate is that fraction rewritten with 1 in the denominator: 240 miles in 4 hours is 60 miles per 1 hour. Getting to the unit rate first makes almost every rate question shorter.
A proportion is a statement that two ratios are equal, and it is the workhorse for "if this much costs that much, what does this other amount cost." Three kilograms of a compound cost $7.50; what do 8 kilograms cost? Write 3 kg / $7.50 = 8 kg / $x, cross-multiply to get 3x = 60, so x = $20. Check it with the unit rate: $7.50 ÷ 3 = $2.50 per kilogram, and $2.50 × 8 = $20. ✓
The rule that actually matters in a proportion is not "cross-multiply" — it is that the same quantity must sit in the same position on both sides. Kilograms over dollars on the left means kilograms over dollars on the right. Writing 3/7.50 = x/8 instead is a different equation with a different, wrong answer, and it is the most common setup error there is. Percent is the same machinery with 100 fixed as the denominator, and it has its own lesson.
Dimensional analysis — the one method
Treat a unit as a symbol that multiplies and divides exactly like a variable. Kilometers cancel kilometers the same way x cancels x. That single permission is the whole technique, and everything below is a consequence of it.
Every conversion statement hands you two fractions, and both of them equal 1. From "1 hour = 60 minutes" you get 60 min / 1 hr and you get 1 hr / 60 min. Neither is more correct than the other. You choose the one whose top or bottom cancels the unit you are trying to get rid of, and that is the only criterion.
The procedure, in full. Write the given quantity as a fraction with its units attached. Multiply by conversion fractions, each oriented so the unit you are leaving appears once above and once below. Cross out the cancelled units on the page. Multiply the numbers only at the very end, in one pass. Then read what units survived.
Worked in line: 90 kilometers per hour into meters per second. (90 km / 1 hr) × (1,000 m / 1 km) × (1 hr / 3,600 s). Kilometers cancel against kilometers; hours cancel against hours; meters and seconds are all that remain. Numbers last: 90 × 1,000 ÷ 3,600 = 25 meters per second. Sanity check in the other direction: 25 m/s × 3,600 s = 90,000 m = 90 km in an hour. ✓
Here is why the extra writing pays for itself. The surviving units are a verifiable prediction. If you asked for meters per second and the algebra leaves you holding kilometer-seconds per hour squared, you know you are wrong before doing a single multiplication, and the offending factor is the one whose unit failed to cancel — so you know not just that you are wrong but exactly where. Nothing else on the Math section tells you that for free.
Do not decide multiply-or-divide by feel. "Bigger unit to smaller unit means multiply" survives one-step conversions and collapses on the two-step and mixed-direction chains this skill actually asks for. Orientation-by-cancellation never has that failure mode, and it costs about eight seconds of writing.
When scaling is legal, and what happens to areas
Two quantities are proportional when y = kx for some fixed k: the ratio y/x is the same at every point, and the graph passes through the origin. That, and only that, is the license to say "double the input, double the output" or to scale from a single data point.
A fixed component destroys proportionality. With cost = 4 + 2d, the ratio cost/distance is $2.80 per mile at 5 miles and $2.40 per mile at 10 — it changes at every distance, so there is no single per-mile number to scale with. Whenever a scenario contains a flat fee, a deposit, a base charge, a setup cost, or a starting amount, scaling from one data point is wrong. This is the same distinction as slope versus intercept, wearing different clothes.
Inverse proportion is the other family: xy = k, so one quantity rises exactly as fast as the other falls and their product stays fixed. Five machines take 12 hours, so the job is 60 machine-hours; eight machines take 60 ÷ 8 = 7.5 hours. The trap is handling it as a direct proportion and getting 12 × 8/5 = 19.2 — more machines producing more hours, which the situation itself rules out. Read the direction off the story before setting up any proportion.
Scale factors and dimensions. If lengths are scaled by a factor k, areas scale by k squared and volumes by k cubed. A 1:20 model has 1/400 of the surface area and 1/8,000 of the volume of the real thing. This is the same fact as the squared-conversion rule, and it appears as map scale, model scale, and "if the radius doubles, what happens to the area" — one idea, three costumes.
Mechanism
Why a conversion factor is allowed to change the number
A statement like "1 meter = 100 centimeters" is not a recipe; it is an equation between two names for the same length. Divide both sides by 1 meter and you get 1 = 100 cm / 1 m — a fraction that is literally the number one, wearing units. Multiplying any quantity by it therefore cannot change the quantity. It can only change how the quantity is described, which is why the number in front is free to move while the physical amount is not, and why the orientation is a free choice: 1 m / 100 cm is the same number one, flipped over. The squaring rule then falls out in a single line and never has to be memorized separately. A square meter means (1 m)(1 m), and each of those meters is 100 cm, so 1 m² = (100 cm)(100 cm) = 10,000 cm². The factor gets used once per dimension — once for a length, twice for an area, three times for a volume — because an area is a product of two lengths and a volume is a product of three.
Worked examples
Fully worked — a two-factor chain, units written at every step
- 01Problem: a conveyor carries 45 crates past a point every hour, and each crate holds 24 cans. How many cans pass that point in 20 minutes?
- 02Write the given quantity as a fraction with units: 45 crates / 1 hour. Then list the conversions available, each as a fraction equal to 1: 24 cans / 1 crate, and 1 hour / 60 minutes.
- 03Orient the first factor so the unit you want gone cancels. You want cans, not crates, so put crates underneath: (45 crates / 1 hr) × (24 cans / 1 crate). Crates cancel. Numbers: 45 × 24 = 1,080 cans per hour.
- 04Now the time. You want minutes, not hours, so hours must go underneath: (1,080 cans / 1 hr) × (1 hr / 60 min) = 18 cans per minute. Hours cancel.
- 05Multiply by the 20 minutes the question asked about: 18 cans/min × 20 min = 360 cans. Minutes cancel, and the only surviving unit is "cans" — which is what the question asked for. That agreement is the check, not a formality.
- 06Answer: 360 cans. Second route as confirmation: 20 minutes is one third of an hour, and 1,080 ÷ 3 = 360. ✓
One step hidden — the rate is given upside down
- 01Problem: a press prints one poster every 8 seconds. How many posters does it print in 1.5 hours?
- 02Read the rate carefully. "One poster every 8 seconds" is 8 seconds per poster — seconds on top. The question asks for posters, so the fraction you need is the flip: 1 poster / 8 seconds.
- 03Convert the time so it can cancel: 1.5 hr × (60 min / 1 hr) × (60 s / 1 min) = 5,400 seconds.
Two steps hidden — a squared unit inside the problem
- 01Problem: a sealant covers 6 square meters per liter. A wall panel measures 150 cm by 80 cm. How many whole panels can one liter of sealant cover? (1 meter = 100 centimeters)
- 02Work out the panel's area in the units it was given in, before converting anything: 150 cm × 80 cm = 12,000 square centimeters.
Solve alone
- 01A cargo drone burns 1.8 liters of fuel per 100 kilometers at cruise. It carries 27 liters of usable fuel and cruises at 150 kilometers per hour. Ignoring takeoff and landing, for how many hours can it stay at cruise?
In your own words
In one sentence: why does multiplying a quantity by (1 hour / 60 minutes) change the number in front of it without changing the quantity itself — and what does that fact tell you about how to choose between that fraction and (60 minutes / 1 hour)?
Named traps
- Unsquared conversion factor
- Converting an area with the length factor, or a volume with the area factor. One square meter is 10,000 square centimeters, not 100. Anything carrying "square" or "cubic" takes the factor to that power — including a squared unit hidden inside a rate, like grams per cubic centimeter or people per square mile, where the word is easy to read straight past at speed.
- Upside-down factor
- The conversion fraction used in the orientation that does not cancel. It is the cheapest trap to catch and the most expensive to miss, because the tell is immediate — the wrong unit survives — and the damage is not a small slip: a mis-oriented factor puts you off by the square of the conversion number, so a flipped minutes-to-hours factor lands you a factor of 3,600 away rather than 60.
- Inverted rate
- Using seconds-per-item where items-per-second was needed, or dollars-per-kilogram where kilograms-per-dollar was needed. The two are the same relationship and only one of them cancels the unit you are holding. This is the trap a magnitude check cannot catch when the conversion number is close to 1, which is why the cancellation has to be written rather than felt.
- Part-to-part read as part-to-whole
- Reading 5:3 as "5 out of 8" when the question wants the comparison, or as "5 out of 3" when it wants the share. Count parts first: 5:3 is eight parts, so 5/8 and 3/8 are the shares of the total and 5/3 is the ratio of one part to the other. The exam offers both numbers as choices on the same item.
- Assumed proportionality
- Scaling from a single data point in a scenario that contains a flat fee, deposit, base charge or starting amount. A "cost per unit" computed by dividing a total that includes a fixed charge is not a rate, and multiplying by it is not valid at any other quantity than the one it came from.
- Averaged rates
- Combining two rates by taking their mean, or combining two jobs by adding the times each takes alone. Rates add only when the things they measure genuinely pool — two pumps into one tank — and an average speed for a whole trip is total distance over total time, never the average of the leg speeds.
The 800-level margin
At 1500 the method is not what is costing points. Six things are: rates whose denominator is not one, squared units hidden inside a rate, chains that convert in two directions at once, expression-selection items with no numbers to sanity-check against, the average-of-rates family, and a short list of execution errors that survive knowing all of the above.
Rates whose denominator is not one. "1.8 liters per 100 kilometers." "$54 for every 4 posters." "3 grams per 6 meters of filament." These are already complete rates; the error is reading the second number as a conversion factor to be applied somewhere else. Two clean ways through: reduce to a unit rate before anything else (0.018 L/km), or carry the fraction whole and let cancellation handle it (1.8 L / 100 km). Both work. Starting one way and finishing the other is where the factor of 100 goes missing.
Squared and cubed units hidden inside a rate. Milligrams per square centimeter, dollars per square foot, grams per cubic centimeter, people per square mile. Converting one of these means two different powers in the same chain — the numerator's factor to the first power, the denominator's to the second or third — and the item is built so that applying one power to both produces a listed answer. When a rate has an area or a volume in its denominator, write the denominator's conversion out as a product of identical factors rather than reaching for a remembered number.
Chains that convert in two directions at once. Grams going up to milligrams while square meters come down to square centimeters; dollars per gallon into cents per liter. Every extra factor is another opportunity to be right about orientation in one place and wrong in another, and the two errors can partially hide each other in the final magnitude. Writing the units and striking them out is not a beginner's crutch on these items; it is the only check that exists.
Expression-selection items — "which expression gives the number of days" — hand you letters instead of numbers, which removes the rough estimate you would normally use to sniff-test an answer. The substitute is to pick your own numbers: assign each letter a small value you can compute with in your head, work the answer out arithmetically, then evaluate all four expressions at those same values and keep the one that matches. Choose values that cannot coincide — avoid 1, which hides every multiplication, and avoid 2, where doubling and squaring give the same result.
Averages of rates. Average speed for a journey is total distance divided by total time, full stop. Drive 60 miles out at 30 mph and the same 60 miles back at 60 mph: 2 hours out, 1 hour back, 120 miles in 3 hours, so 40 mph — not the 45 you get by averaging the two speeds. The mean of the rates is correct only when the two legs take the same amount of TIME, which is almost never what an item describes, and 45 will be sitting there as a choice.
Execution errors, which is where the remaining points at this level actually live. First and largest: answering the right question about the wrong quantity — reporting the new total when the question asked how much was added, the part when it asked for the whole, the per-unit figure when it asked for the total. It is beaten by rereading the last eight words of the question after computing, not before. Second: dropping a factor of 1,000 between grams and kilograms, milliliters and liters, meters and kilometers. This is the single most common slip in the domain, and it is also the most visible — an answer that is 1,000 or 1,000,000 away from your estimate is a unit error, never an arithmetic one, and the credited answer is usually the choice sitting exactly that many orders of magnitude away from the one you computed.
Three more that are pure rather than reasoning. Reading "45 minutes" as an hour, or "during the first three years" as "in the third year." Rounding mid-chain: two thirds carried through three more multiplications as 0.67 will miss a band that 2/3 would have hit, so round once, at the end, or not at all. And the final unit itself — if the question asks for dollars per hour and the unit still standing at the end of your work is dollars per minute, everything else being right does not help. Write the units you are being asked for at the top of the scratch area before you start, and compare against them last.
One note on tooling. will do the arithmetic of an ugly proportion faster than you can cross-multiply — put each side on its own line and read the intersection. What it cannot do is notice that you set the proportion up with kilograms opposite pounds. Conversion is the one part of this domain that no calculator checks for you.
Retrieval — with feedback on every choice
A bottling machine fills 12 bottles every 5 seconds. At this rate, how many bottles does the machine fill in 1.5 hours?
RATIOS, RATES, PROPORTIONS, UNITS — reference card "per" = a fraction bar. "of" = multiply. Write every rate as a fraction with units. Every conversion gives TWO fractions, both equal to 1. Pick the one that cancels. Write units at every step. The surviving unit is the check — and it is free. Areas square the factor, volumes cube it: 1 m = 100 cm -> 1 sq m = 10,000 sq cm -> 1 cu m = 1,000,000 cu cm Ratio a:b has a+b parts. Share of whole = a/(a+b). Comparison = a/b. Not the same. Proportion: same quantity in the same position on both sides, THEN cross-multiply. Proportional means y = kx, through the origin. A flat fee makes scaling illegal. Inverse: xy = k. More workers, fewer hours, same product. Rates that pool ADD. Never average two rates; never add two solo times. Average speed = total distance / total time. Always. Rate given per 100 km or per 4 items: reduce to a unit rate first, or carry it whole. Off by 1,000 or 1,000,000 from your estimate = a unit error, not an arithmetic one. Last check, every time: does the surviving unit match the unit the question asked for, and did it ask for the amount ADDED or the new TOTAL?
Every item on this page is Meridian-original, written to match the Digital SAT's format and difficulty — it is not a real SAT question. The only source that matches the live test exactly is College Board's own Bluebook and Question Bank.
A bottling machine fills 12 bottles every 5 seconds. At this rate, how many bottles does the machine fill in 1.5 hours?
- A216
This converts 1.5 hours to 90 minutes and then multiplies by a rate measured in seconds: 2.4 × 90. The conversion was done, just not all the way down to the unit the rate is written in. The units would have caught it — bottles per second times minutes leaves a meaningless mixture, not bottles.
- B2,250
This uses the rate upside down — 5 seconds per 12 bottles rather than 12 bottles per 5 seconds — giving 5,400 × 5/12. Written as a fraction the error is visible: seconds per bottle multiplied by seconds does not cancel to bottles.
- 12,960
Correct. Convert the time first: 1.5 hr × 3,600 s/hr = 5,400 seconds. The unit rate is 12 ÷ 5 = 2.4 bottles per second. Then (2.4 bottles / 1 s) × 5,400 s = 12,960 bottles — seconds cancel, bottles survive. Check by a different route: 5,400 seconds is 1,080 five-second intervals, and 1,080 × 12 = 12,960. ✓
- D64,800
This multiplies the 5,400 seconds by 12 without dividing by 5 — using "12 bottles" as though it were the per-second rate. The 5 in "every 5 seconds" is not decoration; it is the denominator of the rate.
Traps tested: Incomplete unit conversion · Inverted rate · Partial rate applied
A protective coating is applied at a rate of 4 grams per square meter. Given that 1 gram = 1,000 milligrams and 1 meter = 100 centimeters, what is the application rate in milligrams per square centimeter?
- A0.0004
This converts the area correctly (dividing by 10,000) and then reports the result as milligrams while never converting the mass out of grams. The answer 0.0004 is right — in grams per square centimeter. Reading the final unit off the question rather than off your own work is what makes this one hard to catch.
- 0.4
Correct, and the two factors move in opposite directions, which is the point of the item. Mass up: 4 g/m² × (1,000 mg / 1 g) = 4,000 mg/m². Area down, with the factor squared because it is an area: 1 m² = (100 cm)(100 cm) = 10,000 cm², so 4,000 mg per 10,000 cm² = 0.4 mg/cm². Check the size: one square centimeter is a ten-thousandth of a square meter, so it should receive a small fraction of a gram — 0.4 mg is 0.0004 g. ✓
- C40
This does the mass conversion correctly and applies the length factor once to the area: 4,000 ÷ 100. It is off by exactly 100, the signature of a squared unit converted with an unsquared factor.
- D400,000
This multiplies by both conversion numbers without checking either orientation: 4 × 1,000 × 100. Multiplying by 100 makes the coating denser on the smaller unit of area, which is backwards — a square centimeter must receive less coating than a square meter, not more.
Traps tested: Incomplete unit conversion · Unsquared conversion factor · Orientation unchecked
A batch of mortar weighing 72 kilograms is made of sand and cement in a ratio of 5 to 3 by mass. How many kilograms of cement must be added to the batch so that the ratio of sand to cement becomes 5 to 4?
- A5
This re-splits the same 72 kilograms in the new ratio — 40 sand and 32 cement — and reports 32 − 27 = 5. But adding cement cannot remove sand: the sand is fixed at 45 kilograms throughout, and the total has to grow, not stay at 72. Holding a total constant while something is added to it is the specific error here.
- 9
Correct. The ratio 5:3 is 8 parts, so one part is 72 ÷ 8 = 9 kg: sand 45, cement 27. Adding cement leaves the sand at 45, and 5:4 with sand at 45 means cement must be 45 × 4/5 = 36. So the amount added is 36 − 27 = 9 kg. Check the result: 45 to 36 divides by 9 to give exactly 5 to 4, and the new total is 81 kg. ✓
- C27
This is the cement already in the batch. Every step up to it is right; the question asked how much must be ADDED, and this reports what is currently there — the most common way to lose a question you have fully solved.
- D36
This is the cement the batch must END with. Again the reasoning is complete and correct, and the final line asked for the amount added, which is the difference between this and the 27 already present.
Traps tested: Fixed total under addition · Answered wrong quantity
A 3-D printer extrudes filament at a constant 25 millimeters per second. Each meter of the filament has a mass of 4 grams, and the filament costs $25 per kilogram. What is the cost, in dollars, of the filament the printer uses during 45 minutes of continuous printing?
- $6.75
Correct. Time: 45 min × 60 = 2,700 s. Length: 25 mm/s × 2,700 s = 67,500 mm, and 67,500 ÷ 1,000 = 67.5 m. Mass: 67.5 m × 4 g/m = 270 g, and 270 ÷ 1,000 = 0.27 kg. Cost: 0.27 kg × $25/kg = $6.75. Every unit cancels in turn — seconds, millimeters, meters, grams — and dollars is the only one left. ✓
- B$9.00
This is the correct method run on a full hour instead of 45 minutes: 3,600 s gives 90 m, 360 g, 0.36 kg, $9.00. It is the answer to a question the item did not ask, and it is on the list precisely because a reader who has understood the whole chain is the one most likely to skim the duration.
- C$1,687.50
This applies the price to the length: 67.5 × 25. The price is per kilogram, so multiplying it by meters gives dollar-meters per kilogram — the mass step was skipped entirely, and the units say so before the arithmetic does.
- D$6,750
This reaches the correct 270 grams and then prices it as though grams were kilograms: 270 × 25. It is off by exactly 1,000 from the credited answer, which is the fingerprint of a dropped metric prefix rather than a reasoning error.
Traps tested: Answered wrong quantity · Unit blind multiplication · Incomplete unit conversion
A nursery waters its planting beds at a rate of m milliliters of water per square meter per day. It has b beds, each with an area of a square meters. Which expression gives the number of days the nursery can water all of its beds from a full tank holding L liters of water? (1 liter = 1,000 milliliters)
- AL / (mab)
This divides the supply by the daily use, which is the right structure, and never converts liters to milliliters. Liters over milliliters-per-day does not cancel to days, and the answer comes out 1,000 times too small. Testing with numbers exposes it instantly: at m = 2, a = 3, b = 4, L = 5, one tank is 5,000 mL and the beds use 24 mL a day, which is far more than the 0.2 days this gives.
- BL / (1000mab)
This converts, but in the direction that makes the tank smaller. A liter is bigger than a milliliter, so a tank measured in milliliters must carry a larger number, not a smaller one — the factor of 1,000 belongs on top with L, not underneath it.
- Cmab / (1000L)
This is the whole ratio upside down: daily use divided by supply, which gives the fraction of the tank consumed per day rather than the number of days the tank lasts. The tell is dimensional — milliliters per day divided by milliliters leaves 1/day, the reciprocal of what was asked for.
- 1000L / (mab)
Correct. Daily use is m mL per square meter per day × (a square meters per bed) × (b beds) = mab milliliters per day. The tank holds L liters × (1,000 mL per liter) = 1000L milliliters. Days = 1000L ÷ mab, and the units confirm it: milliliters divided by milliliters-per-day leaves days. Test it: m = 2, a = 3, b = 4, L = 5 gives 5,000 mL against 24 mL per day, which is 5000/24 days — exactly what 1000L/(mab) returns. ✓
Traps tested: Incomplete unit conversion · Inverted conversion direction · Inverted ratio
One pump moves water at 0.75 cubic meters per minute. A second pump moves 250 liters per minute. Running at the same time, how many minutes will the two pumps take to fill an empty 30,000-liter tank? (1 cubic meter = 1,000 liters)
- 30
Correct. Put both rates in the same unit first: 0.75 m³/min × 1,000 L/m³ = 750 L/min. Rates pool, so together they move 750 + 250 = 1,000 liters per minute, and 30,000 ÷ 1,000 = 30 minutes. Check in the other unit system: the tank is 30 m³, the pumps are 0.75 and 0.25 m³/min, and 30 ÷ 1 = 30. ✓ The two systems agreeing is what confirms the conversion, not just the arithmetic.
- B40
This is 30,000 ÷ 750 — the first pump alone. The conversion is done correctly and then the second pump is left out of the sum, which is a likely slip precisely because the conversion feels like the hard part of the question and finishing it feels like finishing the question.
- C60
This averages the two rates instead of adding them: (750 + 250) ÷ 2 = 500 L/min. Averaging is what you do to compare two pumps; adding is what you do when they run into the same tank at the same time. An average would mean two pumps fill the tank more slowly than the faster one alone.
- D120
This is what the unconverted numbers produce: 0.75 added to 250 is 250.75, and 30,000 ÷ 250.75 rounds to about 120 — the first pump has been made 1,000 times too small and contributes almost nothing. A rate given in cubic meters cannot be added to a rate given in liters until one of them is rewritten.
Traps tested: Answered wrong quantity · Averaged rates · Incomplete unit conversion
Up next
Percentages
Percent change, successive change, and why a 20% rise then a 20% fall is not where you started.
30 min