Two-variable data: models and scatterplots
Line of best fit, slope in context, and the difference between interpolating and inventing.
~30 min · prequestion, worked examples, retrieval practice
A line of best fit is not the data — it is a claim about the data, and every question on this skill lives in the gap between the two. The dots are what happened; the line is what a model says should have happened; the difference between them has a name, a sign, and a question type built on it. Problem-Solving & Data Analysis is about 15% of the Math section, and this skill is the one where the arithmetic is trivial and the reading is not: nearly every point lost here is lost to answering a correct question about the wrong quantity.
Before you read on
Two or three questions on exactly what this lesson teaches. Being wrong here is fine — it's the fastest way to find out what to pay attention to next.
Before any teaching. A scatterplot relates x, the number of minutes a cup of coffee has been sitting on a table, to y, its temperature in degrees Celsius. The line of best fit is y = 78.6 − 1.4x. Which is the best interpretation of the number 1.4?
A line of best fit predicts a value of 61 for a certain data point. The value actually measured at that x is 68. What is the residual for this point, and where does the point sit relative to the line?
A table gives a quantity at times t = 0, 1, 2, and 3 as 500, 460, 423.2, and 389.344. Is the relationship better modeled by a linear or an exponential function, and on what evidence?
What the question is actually testing
This skill point covers data on two variables at once: a scatterplot, a table of paired values, or a fitted model given as an equation. What you are asked to do falls into five jobs, and only five — interpret a slope, interpret an intercept, produce a predicted value, compare a prediction with a measurement (a residual), or decide which shape of model the data actually has. The arithmetic in all five is one multiplication and one addition. The difficulty is entirely in knowing which of the five you were asked for.
College Board's published test specification puts Problem-Solving & Data Analysis at about 15% of the Math section — on the order of five to seven questions. How that splits across the domain's seven skill points is not published, so any claim that you should expect a specific number of scatterplot items is a prep-industry estimate reverse-engineered from released material, not an official figure. Treat it as a planning assumption.
One structural fact makes the whole skill cheaper than it looks: the model is always handed to you. Meridian has not seen a released Digital SAT item that asks a student to compute a line of best fit by hand, and there is no formula for one on the reference sheet. You get an equation, a described line, or a graph with the line already drawn, and the work is reading it. That is why this skill rewards care rather than technique.
What is genuinely new here, compared with the linear-equation and linear-function skills next door, is the gap between model and measurement. Everywhere else on the Math section the equation is the truth. Here the equation is a summary of something messier, the dots do not sit on the line, and the exam has a question type built specifically on that distance.
Foundations — scatterplots from zero (skip this block if "line of best fit" is already obvious)
If you can look at a scatterplot with a fitted line and immediately say what one dot means, what the line means, and how far apart they are, skip ahead. If any of that is fuzzy, this is the highest-value block on the page, because everything later is a sentence about these objects.
A scatterplot shows one thing measured twice. Each dot is a single case — one city, one student, one plant, one year — and its horizontal position is one measurement of that case while its vertical position is the other. Twenty dots means twenty cases, not twenty numbers.
Read the axes before the dots, every time. The axis labels carry the whole meaning, and two riders on them cause more lost points than anything else in this skill: a shifted origin ("years since 1995", so 1998 is x = 3, not x = 1998) and a scaling rider ("population, in thousands", so a height of 46.5 means 46,500 people).
Association is the pattern in the cloud. If the dots drift upward as you move right, the association is positive; downward, negative; if they hug a pattern tightly, it is strong, and if they scatter loosely around it, weak. Association is not causation — two quantities can move together because one drives the other, because something else drives both, or by accident, and a scatterplot cannot tell those apart.
The line of best fit is a single straight line drawn through the cloud to summarize that pattern. Three things about it are worth fixing now. It is a summary, not a boundary — dots are expected on both sides of it. It is not required to pass through any dot at all, and usually passes through none of them. And it is a claim about the trend, so it can be a perfectly good line through data that no straight line describes well.
That gives the distinction the entire skill runs on. The dots are ACTUAL values: what was measured. The line gives PREDICTED values: what the model says to expect at that x. The exam signals which one it wants with the words "predicted", "the model", "the line of best fit" on one side, and "measured", "recorded", "the data point", "actual" on the other. The exam writes the model as y = 812 − 6.4x, which quietly hides that this y is a prediction; when you copy a model onto your scratch paper, writing it as ŷ = 812 − 6.4x costs a second and keeps the two apart for the rest of the question.
Getting a predicted value out of the model: substitute the x you were given. From a graph rather than an equation, find the x on the horizontal axis, go up to the line — not to a nearby dot — and read across to the vertical axis.
The slope of the line of best fit is a rate in the same sense it is everywhere else: y-units per one x-unit, carrying the sign of the direction. Compute it from two points that lie ON THE LINE. Two data points give you the slope of the segment joining two dots, which is a different line and almost never the same number.
The y-intercept of the line of best fit is the predicted y when x = 0, exactly as in any linear equation. Whether that number means anything in the real situation depends on whether x = 0 is inside the range of the data — a question taken up in the 800-level block, because it is where strong students lose this item.
A residual is the gap between one dot and the line, straight up or down: residual = actual − predicted. Positive means the dot is above the line and the model underestimated that case; negative means the dot is below the line and the model overestimated it. It is measured in the y-variable's units, and it belongs to one data point, not to the model as a whole.
A curve of best fit is the same idea with a curved model instead of a straight one. On the Digital SAT the curved model is almost always exponential: y = a·b^x, where a is the predicted value at x = 0 and b is the multiplier per one x-unit. b greater than 1 is growth, b between 0 and 1 is decay, and the percent change per step is (b − 1) expressed as a percentage — 1.2 is a 20% increase, 0.85 is a 15% decrease.
The five jobs, and how to tell which one you were given
Step 1 — name x and y with units, in writing, including the riders. "x: years after 2005. y: subscribing households, in thousands." Ten seconds, and it is what makes the difference between an answer of 24 and an answer of 24,000 at the end.
Step 2 — decide which of the five jobs the question is asking for, before computing anything. Is it a RATE (the slope, per one x-unit)? A LEVEL (a predicted value of y at a stated x)? A CHANGE OVER AN INTERVAL (the slope times the interval's length)? An INPUT (the x that produces a stated y, so solve rather than substitute)? Or a RESIDUAL (a comparison between one measurement and the model)? The four you were not asked for are, reliably, three of the four answer choices.
Step 3 — for a slope interpretation, say it as a full sentence with units and a direction before looking at the options: "for each additional [one x-unit], the predicted [y-quantity] increases/decreases by [number] [y-units]." A choice that omits "predicted", or reports the number without the per-one-unit, or drops the direction, has failed a part of that sentence.
Step 4 — for an intercept interpretation, say: "when x is 0, the model predicts y = b." Then translate x = 0 back into the situation — the year 2005, the day of arrival, zero minutes of use — because the answer choices will be phrased in the situation's language, not in x.
Step 5 — for a residual, subtract in the fixed order, actual minus predicted, then check it with the identity predicted + residual = actual. Then translate the sign into English before you answer, because the question often asks for "how much the model overestimates" rather than for a signed number.
Step 6 — for a model-shape decision, run two rows of arithmetic across the table. Constant DIFFERENCES between consecutive y-values (at evenly spaced x) means linear. Constant RATIOS means exponential. If the x-values are not evenly spaced, compare rates over each interval instead of raw differences. And if the description is verbal rather than tabular, the tell is the same one in words: a constant AMOUNT per step is linear, a constant PERCENTAGE per step is exponential.
Mechanism
Why residuals are the currency, and why the line has no authority outside the data
The line of best fit is not drawn by eye and it is not the average of anything obvious. It is chosen to make the residuals collectively as small as possible — specifically, to minimize the sum of their squares. Squaring does two jobs at once: it stops a point 5 above the line from cancelling a point 5 below it, and it makes one large miss cost more than several small ones, which is why a single outlier can pull the whole line toward itself. Three consequences follow, and all three are tested. First, the residual is not an incidental quantity invented for exam questions; it is the exact thing the line was built to control, which is why "how far is this point from the model" is the natural question to ask about a fitted line. Second, the residuals of a least-squares line with an intercept sum to zero by construction — so being told that they sum to zero tells you nothing whatsoever about whether the model fits. What carries information is their PATTERN: scattered randomly around zero means the straight line captured the shape, while a systematic run of positives, then negatives, then positives means the relationship is curved and the line is wrong in a way more data will not fix. Third, and most costly: the line was fitted using only the dots that exist. Inside the window of x-values where data were collected, the line is constrained on both sides by real measurements, which is what makes a prediction there defensible — that is interpolation. Outside that window nothing constrained it. Extending the line to x = 40 when the data stop at x = 10 does not extend the evidence; it assumes that a shape observed over one interval continues over another where it was never observed, which is why a linear model of a child's height fitted from ages 2 to 10 confidently predicts a 3.3-metre adult. The arithmetic will not object. Nothing in the algebra knows where the data stopped, which is why noticing the range is your job and not the model's. The same reasoning explains why the choice between linear and exponential is not cosmetic: adding a constant amount and multiplying by a constant factor agree closely over a step or two and diverge without limit afterwards, so the wrong shape can match the first row of a table perfectly and still be worthless three rows later.
Worked examples
Fully worked — slope, intercept, prediction, and residual from one model
- 01Scenario: "A scatterplot relates x, the number of days after a shipment of avocados arrives at a store, to y, the firmness of a sampled avocado in newtons. Data were collected on days 1 through 9. The line of best fit is y = 46.2 − 4.5x. Interpret the slope; find the firmness the model predicts on day 6; and given that a sample measured on day 6 had a firmness of 17.1 newtons, find the residual and say whether the model over- or underestimates that avocado."
- 02Name x and y with units before anything else. x: days after arrival, data covering days 1 through 9. y: firmness in newtons. The equation returns PREDICTED firmness, so write it as ŷ = 46.2 − 4.5x.
- 03Slope, as a full sentence: −4.5 is the coefficient on x, so for each additional day after arrival, the predicted firmness decreases by 4.5 newtons. The direction is part of the interpretation, not decoration — the sign is what makes it a decrease.
- 04Intercept: 46.2 is the predicted firmness at x = 0, the day the shipment arrived. Worth noticing that x = 0 sits just outside the data window of days 1 through 9, so this is a one-day extrapolation — small enough to be defensible here, and exactly the thing that stops being defensible when the gap grows.
- 05Prediction on day 6 — a LEVEL, so substitute: ŷ = 46.2 − 4.5(6) = 46.2 − 27 = 19.2 newtons.
- 06Residual — a comparison, so subtract in the fixed order, actual minus predicted: 17.1 − 19.2 = −2.1 newtons.
- 07Translate the sign into English: negative means the measurement came in below the line, so that avocado was softer than the model expected and the model OVERESTIMATED its firmness by 2.1 newtons.
- 08Check with the identity: predicted + residual = 19.2 + (−2.1) = 17.1, which is the measured value. ✓ Run that check every time; it catches a reversed subtraction in about three seconds.
One step hidden — slope from two points on the line, with a scaling rider
- 01Scenario: "A scatterplot relates x, the number of years after 2005, to y, the number of households in a county subscribing to a fiber-internet service, in thousands. Data were collected for 2005 through 2017. The line of best fit passes through the points (2, 18.5) and (10, 46.5). Write the model, then state the slope as a rate in households per year."
- 02Both given points are stated to be ON THE LINE, which is what makes them usable for slope. Two data points would not be — dots are what the line summarizes, not what it is made of.
- 03Slope: (46.5 − 18.5)/(10 − 2) = 28/8 = 3.5, in the axis's own units, which are thousands of households per year.
- 04Constant: substitute (2, 18.5) into ŷ = 3.5x + b → 18.5 = 7 + b → b = 11.5, so ŷ = 3.5x + 11.5. Check on the point not used: 3.5(10) + 11.5 = 46.5. ✓
Two steps hidden — choosing the shape from a table, then using it
- 01Problem: "A platform reports its active accounts at the end of each year: 2018, 6,000; 2019, 7,200; 2020, 8,640; 2021, 10,368. Model the count as a function of t, the number of years after 2018, and predict the count at the end of 2023."
- 02Test linear first, because it is cheaper. Differences: 7,200 − 6,000 = 1,200; 8,640 − 7,200 = 1,440; 10,368 − 8,640 = 1,728. Not constant, so no straight line fits this table.
- 03Test exponential. Ratios: 7,200/6,000 = 1.2; 8,640/7,200 = 1.2; 10,368/8,640 = 1.2. Constant, so the model is exponential with growth factor 1.2 — a 20% increase per year.
Solve alone
- 01Problem: "A scatterplot relates x, the number of hours a rechargeable battery has been in use since a full charge, to y, the percentage of charge remaining. Data were collected for 1 ≤ x ≤ 8, and the line of best fit passes through (2, 74) and (6, 42). (a) Write the equation of the line of best fit. (b) A battery measured at x = 5 had 51% of its charge remaining; find the residual and say whether the model over- or underestimates it. (c) Say why the model should not be used to predict the charge remaining at x = 30."
In your own words
In one sentence: why does a positive residual mean the model underestimated that data point — what exactly is being subtracted from what, and where does that put the dot relative to the line?
Named traps
- Residual sign flip
- Computing predicted − actual instead of actual − predicted, or computing it correctly and then reading the sign backwards. The definition runs one way only, and the three phrases that travel together are: positive residual, dot above the line, model underestimates. A distractor carrying the correct magnitude with the opposite sign appears on essentially every residual item, because it is the error the item was written to catch.
- Data point used as a model point
- Computing the slope of the line of best fit from two dots on the scatterplot rather than two points on the line. The line is a summary that generally passes through none of the data, so the segment joining two dots has its own slope and it is not the model's. Use a stated equation, or points explicitly described as lying on the line, or two clean grid crossings the drawn line passes through.
- Blind extrapolation
- Feeding the model an x far outside the range where data were collected and treating whatever comes back as a prediction the data support. The algebra never complains, which is the problem. This includes the quiet version: interpreting the y-intercept as a real quantity when x = 0 lies well outside the observed range, so the model has never been checked anywhere near it.
- Rate, level, and interval confused
- Reporting the slope when a value was asked for, a value when a change was asked for, or the one-unit change when the question named a multi-unit interval. Change over an interval is the slope times the interval's length, and the interval from 2001 to 2011 is ten steps, not eleven. On a well-built item all three numbers are printed as choices, and all three are correct answers to questions that were not asked.
- Percent-versus-amount misfit
- Forcing a straight line onto data that changes by a constant factor, or the reverse. The tell in a table is differences versus ratios; the tell in a sentence is an amount ("falls by 40 units a year", linear) versus a percentage ("falls by 8% a year", exponential). Its close relative: using the percentage itself as the base — writing 0.15 where a 15% annual decline requires a factor of 0.85, or 1.15 for a 15% rise.
- Axis-label unit slip
- Ignoring a rider on an axis or a variable definition and answering in the model's internal units instead of the question's. "In thousands" turns a slope of 2.4 into 2,400 per year; "years since 1995" means the answer 8 may need to be reported as 2003; "per 100,000 residents" means the model's output is a rate, not a count. Convert once, at the end, after underlining the units the question asked for.
The 800-level margin
By this point the method is not what separates 1500 from 1600 on this skill. Six things are: the predicted/actual distinction hidden inside ordinary wording, residual plots, exponential models whose time step is not one unit, intercepts that are mathematically fine and physically meaningless, the interval-versus-level family of questions, and a short list of execution errors that survive knowing all of the above.
The wording, first, because it is worth the most. An item does not have to use the word "residual" to be a residual item. "By how much does the model overestimate the value for that city", "how much greater was the recorded amount than the amount the line predicts", "the data point lies how far above the line of best fit" are all the same computation in different clothes. The reverse is also written: an item that mentions a specific measured value but asks only for the model's prediction is testing whether you will subtract when nothing asked you to. Underline which of the two objects — the dot or the line — the final sentence names.
Residual plots. A residual plot puts x on the horizontal axis and the residual on the vertical, with a horizontal line at zero. Read the shape, not the size. Randomly scattered above and below zero with no pattern means the straight-line model captured the relationship. A run of positives, then negatives, then positives — a U or an arch — means the true relationship is curved and a linear model is systematically wrong at the ends and in the middle, no matter how good the correlation looks on the original plot. A fan that widens as x grows means the spread of the data changes with x, so predictions get less trustworthy toward the wide end. And the sum of the residuals is zero for any least-squares line with an intercept, which makes a zero sum an arithmetic identity rather than evidence of anything — a choice offering it as proof of good fit is offering you a true statement that is not relevant.
Exponential models with a non-unit time step. y = a·b^x claims a multiplier of b per ONE x-unit, so anything described per five hours, per decade, or per half-life must be written with the step inside the exponent. A culture that doubles every 5 hours, with h in hours, is N(h) = N₀·2^(h/5) — not 2^(5h), which doubles five times an hour and is off by a factor of millions within a day. A substance with a 12-year half-life is A(t) = A₀·(1/2)^(t/12), equivalently about A₀·(0.944)^t per year, because 0.5^(1/12) ≈ 0.944 — roughly a 5.6% annual decline. Both forms are correct and the exam will print whichever one you did not write, so recognizing the equivalence is faster than re-deriving it.
Meaningless intercepts. A model of heating cost against average January temperature over a range of −4 to 21 °C has x = 0 sitting comfortably inside the data, so its intercept is a genuine prediction. A model of a child's height against age fitted over ages 2 to 10 has an intercept of about 84 cm at age 0, which is not any newborn's height — it is the number a straight line happens to hit when extended somewhere it was never tested. Both intercepts are correct arithmetic. Only one is a fact about the world, and the exam writes items in which the correct choice is an interpretation of the model rather than a claim about reality. Read the choice's verb: "the model predicts" is safe, "the value was" is a claim the data may not carry.
Interval versus level, in the two directions the exam uses. Forward: given the model, the change over any k x-units is slope × k, and the level at a stated x is the substitution — different numbers, both offered. Backward: "the model predicts a fall of 900 over the fifteen-year period, so what is the annual rate" is a division, and "in what year does the model first predict a value below 400" is a solve followed by a translation from t back into a calendar year. That final translation is where the point goes: t = 13 with x defined as years after 1998 is the year 2011, and 13 will be sitting in the choices.
One more that catches strong students: two models on one plot, or one model and one summary statistic. If a plot carries a line of best fit and a horizontal line at the mean, or two fitted lines for two groups, every question names one of them and the other's answer is a choice. The same applies to items pairing this skill with or a sample statistic — the model answers a different question from the interval, and reading which is being asked takes less time than recovering from having answered the other.
Execution errors, which is where the last few points actually live. Rounding a slope before the final multiplication, when 28/8 is exactly 3.5 and 0.33 is not exactly a third. Reporting the predicted value when the residual was asked for, or the residual when the predicted value was asked for. Answering in thousands because the axis was in thousands. Off-by-one on an interval of years. Substituting a year where the model wants years-since. Every one of these produces a number that is on the answer sheet, which is why re-reading the final sentence before selecting is worth more here than anywhere else in the domain — gives you on every Math question and it will graph the model happily, but it cannot tell you which quantity the sentence asked for.
Retrieval — with feedback on every choice
A scatterplot relates x, the number of years since 2000, to y, the total annual rainfall, in millimeters, recorded at a weather station. Rainfall was recorded each year from 2000 through 2018, and the line of best fit for the data is y = 812 − 6.4x.
Which of the following is the best interpretation of the number 6.4 in this context?
TWO-VARIABLE DATA: MODELS AND SCATTERPLOTS — reference card One dot = one case measured twice. Read the axis labels before the dots. Axis riders that cost points: "years since ____" and "in thousands / per 100,000". The line = PREDICTED values. The dots = ACTUAL values. The exam signals which it wants. Slope = y-units per ONE x-unit, with its sign. Take it from two points ON THE LINE, never two dots. Intercept = predicted y at x = 0. Meaningful only if x = 0 is inside the data's range. Residual = actual - predicted. Positive -> dot ABOVE the line -> model UNDERestimates. Check every residual with: predicted + residual = actual. "By how much does the model overestimate?" is a residual question without the word. Change over an interval = slope x interval length. 2001 to 2011 is 10 steps, not 11. Inside the data's x-range = interpolation, supported. Outside = extrapolation, not supported. Table: constant DIFFERENCES -> linear. Constant RATIOS -> exponential. Words: constant AMOUNT per step -> linear. Constant PERCENT per step -> exponential. Exponential y = a*b^x: a = value at x = 0; b = multiplier per one x-unit; percent = (b - 1). 15% decline -> factor 0.85, not 0.15. 20% growth -> 1.2. Doubling every 5 hours -> 2^(h/5). Residual plot: random scatter = linear is fine. Arch or U = curved relationship, model wrong. Residuals summing to zero is an identity of the fitting method, never evidence of fit. Before answering: reread the last sentence and confirm which of the five jobs it named.
Every item on this page is Meridian-original, written to match the Digital SAT's format and difficulty — it is not a real SAT question. The only source that matches the live test exactly is College Board's own Bluebook and Question Bank.
A scatterplot relates x, the number of years since 2000, to y, the total annual rainfall, in millimeters, recorded at a weather station. Rainfall was recorded each year from 2000 through 2018, and the line of best fit for the data is y = 812 − 6.4x.
Which of the following is the best interpretation of the number 6.4 in this context?
- AThe predicted total annual rainfall in 2000 was 6.4 millimeters.
The predicted rainfall in 2000 is the value at x = 0, which is 812 millimeters — the intercept, not the coefficient. This assigns the rate to the starting value, and the giveaway is available without any arithmetic: 6.4 millimeters of rain in a year is not a quantity a weather station would report as a total.
- BIn each year, the recorded rainfall was 6.4 millimeters less than the rainfall the model predicts.
That describes a residual — the gap between a measurement and a prediction — and residuals differ from point to point rather than being fixed at one value for every year. The coefficient on x sets the line's steepness, not its distance from the dots.
- CBetween 2000 and 2018, the predicted total annual rainfall decreased by 6.4 millimeters.
6.4 is the decrease per one year; the decrease across the whole period is that rate times the interval's length, 6.4 × 18 = 115.2 millimeters. A rate and a total change are different quantities, and the exam prints both.
- Each year, the predicted total annual rainfall decreased by 6.4 millimeters.
Correct. 6.4 is the coefficient on x, so it is a rate: millimeters of predicted rainfall per one year, and the minus sign in front of it makes the direction a decrease. Sentence check — "for each additional year after 2000, the predicted total annual rainfall decreases by 6.4 millimeters" — every part of that sentence is present in this choice.
Traps tested: Slope intercept swap · Slope read as residual · Rate read as total
In a greenhouse study, the mass of each plant, in grams, was recorded against the number of days since planting. The line of best fit for the data is y = 1.8x + 4.5, where x is the number of days since planting and y is the mass in grams. One plant measured 30 days after planting had a mass of 52.5 grams.
What is the residual for that plant's data point?
- −6
Correct. Predicted: 1.8(30) + 4.5 = 54 + 4.5 = 58.5 grams. Residual = actual − predicted = 52.5 − 58.5 = −6 grams. Check with the identity: predicted + residual = 58.5 + (−6) = 52.5, the measured mass. ✓ The negative sign says this plant sits below the line, so the model overestimated it by 6 grams.
- B−1.5
This is 52.5 − 1.8(30) = 52.5 − 54, which drops the constant term from the model. The prediction is the whole right-hand side of the equation evaluated at x = 30, not just the term containing x.
- C6
This is the same subtraction run backwards, predicted − actual = 58.5 − 52.5. The magnitude is right and the sign is not, and the sign is what the question carries: a positive residual would mean the plant grew more than the model expected, which is the opposite of what happened here.
- D58.5
58.5 grams is the model's prediction for day 30 — the correct first step, reported as though it were the answer. A residual is a difference between the prediction and the measurement, so the work stops one subtraction early here.
Traps tested: Dropped constant term · Residual sign flip · Answered wrong quantity
For a group of children whose ages ranged from 2 to 10 years, height was recorded against age. The line of best fit for the data is y = 6.1x + 84.2, where x is age in years and y is height in centimeters.
Using this model to predict the height of a 40-year-old gives what value, and is that prediction appropriate?
- A84.2 centimeters; the prediction is not appropriate, because a 40-year-old is not a child.
84.2 is the intercept, the model's predicted height at age 0, not at age 40 — substituting the given input is the step being skipped. The stated reason happens to point in a sensible direction, which is what makes this choice tempting; the value it is attached to answers a different question.
- B244 centimeters; the prediction is not appropriate, because heights cannot exceed about 2 metres.
244 comes from 6.1(40) with the constant term left off. The prediction the model actually makes is 328.2 centimeters, and the reason to reject it is that the data stop at age 10 — not a rule about maximum heights, which the model has no knowledge of either way.
- C328.2 centimeters; the prediction is appropriate, because the line of best fit models the data well.
The arithmetic is right and the justification does not hold. Fitting the data well over ages 2 to 10 is evidence about ages 2 to 10 and about nothing else; the line was never tested at 40, and the answer it returns — a height of over three metres — is what unchecked extrapolation looks like when the situation is familiar enough to notice.
- 328.2 centimeters; the prediction is not appropriate, because age 40 lies far outside the range of ages for which data were collected.
Correct on both halves. Arithmetic: 6.1(40) + 84.2 = 244 + 84.2 = 328.2 centimeters, which is 3.28 metres — a number the situation immediately rejects. The reason is structural: the line was fitted using ages 2 through 10, so nothing in the data constrains it at 40, and the constant growth rate it assumes stops holding long before then. Note the model is sound inside its window: it gives 96.4 cm at age 2 and 145.2 cm at age 10, both reasonable.
Traps tested: Answered wrong quantity · Dropped constant term · Blind extrapolation
The table gives the value V, in dollars, of a piece of equipment at the end of each of four consecutive years: 2018, $24,000; 2019, $20,400; 2020, $17,340; 2021, $14,739.
Which function best models V, in dollars, as a function of t, the number of years after 2018?
- AV(t) = 24,000 − 3,600t
This takes the first year's drop, $3,600, as a constant annual amount. It matches 2019 exactly, which is what makes it tempting, and then predicts $16,800 for 2020 against an actual $17,340. The differences in this table are 3,600, then 3,060, then 2,601 — shrinking, because the same percentage of a smaller value is a smaller amount.
- V(t) = 24,000(0.85)^t
Correct. Ratios: 20,400/24,000 = 0.85; 17,340/20,400 = 0.85; 14,739/17,340 = 0.85 — constant, so the model is exponential with factor 0.85, a 15% annual decline. The anchor is the 2018 value, since t = 0 is 2018. Verify on a row not used to build it: V(2) = 24,000(0.7225) = 17,340, and V(3) = 24,000(0.614125) = 14,739. ✓
- CV(t) = 24,000(0.15)^t
This uses the percentage lost as the multiplier. A 15% decline means 85% of the value is retained, so the factor is 0.85, not 0.15; as written this model predicts $3,600 after one year rather than $20,400 — a check that takes one multiplication.
- DV(t) = 20,400(0.85)^t
The shape and the factor are both right, and the anchor is one year late: this puts $20,400 at t = 0, but t is defined as years after 2018 and $20,400 is the 2019 value. Substituting t = 0 into a candidate model and checking it against the first row of the table catches this immediately.
Traps tested: First difference forced linear · Rate used as factor · Off by one baseline
A scatterplot relates x, the number of years since 1995, to y, the number of registered vehicles in a county, in thousands. The line of best fit passes through the points (4, 63.5) and (16, 92.3).
According to the line of best fit, what is the predicted increase in the number of registered vehicles from 2001 to 2011?
- A24
This is the correct interval change left in the axis's units. The y-axis is labelled "in thousands", so 24 on that axis means 24,000 vehicles, and the question asks for a number of vehicles. Every step of the work here is right and the answer is off by a factor of a thousand.
- B2,400
This is the increase over one year, correctly converted out of thousands. The question names a ten-year span, and change over an interval is the slope times the interval's length — reporting the rate itself answers a question the item did not ask.
- 24,000
Correct. Slope from two points on the line: (92.3 − 63.5)/(16 − 4) = 28.8/12 = 2.4 thousand vehicles per year. 2001 is x = 6 and 2011 is x = 16, an interval of 10 years, so the predicted increase is 2.4 × 10 = 24 thousand vehicles. The axis is in thousands and the question asks for vehicles, so convert once at the end: 24,000. ✓
- D26,400
This multiplies the rate by 11 instead of 10, from counting the years 2001 through 2011 inclusive. There are eleven labelled years in that span but only ten one-year steps between them, and it is the steps that accumulate change: 2011 − 2001 = 10.
Traps tested: Axis scale unit slip · Rate read as total · Off by one interval
A linear model was fitted to eight data points. Listed in order of increasing x, the residuals are 4.2, 1.8, −1.6, −2.8, −2.9, −1.5, 1.4, and 1.4.
Which conclusion about the model is best supported by these residuals?
- AThe residuals sum to 0, so the linear model fits the data well.
The sum is indeed 0, and it carries no information. For any least-squares line with an intercept the residuals sum to zero by construction — it is a property of how the line is fitted, true of a perfect fit and of a hopeless one alike. A true statement offered as evidence for a conclusion it cannot support is the characteristic hard distractor on this item type.
- The residuals are positive at both ends and negative in the middle, so the relationship is curved and a linear model is not appropriate for it.
Correct. The signs run + + − − − − + +, which is a systematic arch rather than random scatter: the line passes below the data at both ends and above it through the middle, which is exactly what fitting a straight line to a curve produces. The evidence is the ordered pattern, not the size of any single residual, and more data of the same kind would deepen the pattern rather than remove it.
- CThe first data point has a residual of 4.2, so the model overestimates that point by 4.2.
The sign is being read backwards. Residual = actual − predicted, so a residual of +4.2 means the measurement came in 4.2 above the line — the model underestimated that point. Positive residual, dot above the line, model underestimates.
- DFour residuals are positive and four are negative, so the model overestimates as often as it underestimates and the fit is appropriate.
Counting signs discards the ordering, which is the only place the information lives. A balanced count is compatible with random scatter and equally compatible with the arch these residuals actually form; it is the fact that the signs change in blocks rather than at random that condemns the model.
Traps tested: Sum zero read as good fit · Residual sign meaning reversed · Sign count read as fit
Up next
Probability and conditional probability
Two-way tables, where the whole skill is choosing the right denominator.
30 min